Which irrational number has the highest imbedded primes?

[Philosophy Explorer]

Take π e.g. Its partial decimal representation is 3.1415929. We know that 3 and 31 are primes and 314 is composite (not prime). Is 3141 a prime or composite? I don't know offhand. I know that 31415 is composite, 314159 I don't know offhand, 3141592 is composite and 31415929 I don't know whether it is prime or composite and so on down the line. The same process can be applied to e and then the question arises, which has more prime numbers in their decimal representations, π or e, when this procedure is applied (there are other procedures that can be applied that may have a higher yield of primes).

Some may ask about how useful this can be and my reply is that as an explorer, I don't care. I just simply want to know.

PhilX

[mickthinks]

Since both numbers' decimal expressions are infinitely long, there seems no reason to believe the procedure you've described would generate a finite number of primes from either of them.

[Philosophy Explorer]

Since both numbers' decimal expressions are infinitely long, there seems no reason to believe the procedure you've described would generate a finite number of primes from either of them.

There should be an effective way of determining which irrational number generates more primes. With respect to the digital density of each digit (0-9), it's already known that there is an even distribution for the digits (for irrational numbers π, e and √2 as listed by the Wolfram website within the limits of error). I believe that the prime distribution of numbers for irrational numbers can be determined to be uneven within an infinite decimal representation.

PhilX

Edit: maybe by taking out the decimal representation to say a billion places might give us an idea.