Skepdick wrote: ↑Wed Feb 19, 2025 10:25 am
You've proven the negation of the entailment. Nothing more. Nothing less.
I have proved the following: ¬(∀T∀P (T⊨¬P)) → (∃T∃P (T⊨P))
ChatGPT: ¬(∀T∀P (T⊨¬P)) → (∃T∃P (T⊨P))
The given logical statement is:
¬(∀T∀P(T⊨¬P))→(∃T∃P(T⊨P))
Let's break this down step by step.
Step 1: Understanding the Components
T⊨P means that the theory T semantically entails the proposition P.
T⊨¬P means that T semantically entails the negation of P.
∀T∀P(T⊨¬P) asserts that every theory T entails every proposition P in its negated form. This means that all propositions are false in every theory.
The negation of this statement, ¬(∀T∀P(T⊨¬P)), means that there exists at least one theory T and at least one proposition P for which T does not entail ¬P, i.e., T⊭¬P.
Step 2: Interpreting the Implication
The right-hand side of the implication states:
∃T∃P(T⊨P)
This means that there is at least one theory T and at least one proposition P such that T entails P.
Thus, the overall statement:
¬(∀T∀P(T⊨¬P))→(∃T∃P(T⊨P))
suggests that if it is not the case that every theory entails the negation of every proposition, then there must exist some theory that entails some proposition.
Step 3: Logical Intuition
This makes sense intuitively. If not every proposition is false in every theory, then at least one proposition must be true in some theory. In other words, if not everything is false, then something must be true. Thus, this formula expresses a fundamental principle of classical logic: if negation does not hold universally, then some positive assertion must hold somewhere.
Concerning ¬(∀T∀P (T⊨¬P)), all that is required is a witness theory T that allows for some truth in one of its models:
ChatGPT: ∀T∀P ( T ⊨ ¬P). Find an example theory for which this statement is false.
Counterexample: Consider the theory T={}, i.e., the empty theory, which contains no axioms. Take any proposition P, say P itself as a single atomic formula. Since T is empty, it imposes no constraints on P. In particular, there exist models where P is true and models where P is false. Thus, T⊭¬P because there exists at least one model of T in which P holds. Since we found a case where the universal quantification fails, the given logical statement is false.
This is a model-theoretically formalized alternative for:
It is not possible that all propositions are false because in that case this very proposition is also false. Hence, there exist true propositions. This can be proven entirely in first-order logic. No need for a truth predicate or a metatheory. I concede, however, the problem caused by trying to recursively enumerate theories (∀T).