Logik wrote: ↑Fri Apr 19, 2019 8:59 pm
PeteOlcott wrote: ↑Fri Apr 19, 2019 7:52 pm
If we are free to choose between the two axioms that you specified then
that would enable me to correctly say that I am talking to a badminton
racket instead of a human being. Because I see the second axiom as really
nothing more than permission to lie, I choose the first axiom.
In my world "abstractions" make contact with the ground and model errors have real-world consequences.
Reality is really complex. Models are really incomplete and model-errors really results in harm.
It is not that the above is not very important, it is that I have been trying for 12,000 hours
over 22 years going as fast as I can to prove my other point and cannot afford to be distracted
by side issues until this point if fully made. With endless digression I would fail to make
my point working 24/7 for a billion years. With zero digression it has already taken 22 years.
So it seems that I have proved my point and correctly refuted
the 1931 Incompleteness Theorem by the following reasoning.
It does not matter if you don't think that refuting the Incompleteness Theorem
is of no consequence the people that would hire me would think otherwise.
Stipulating this definition of Axiom:
An expression of language defined to have the semantic value of Boolean True.
Stipulating this specification of True and False:
Axiom(1) True(F, x) ↔ (F ⊢ x).
Axiom(2) False(F, x) ↔ (F ⊢ ¬x).
Stipulating that formal systems are Boolean:
Axiom(3) ∀F ∈ Formal_System ∀x ∈ Closed_WFF(F) (True(F,x) ∨ False(F,x))
Within the above stipulations the following logic sentence:
∃F∃G (G ↔ ((F ⊬ G) ∧ (F ⊬ ¬G)))
(1) Asserts there exists expressions G of formal system F that are neither true nor false.
(2) Is decided to be false on the basis of Axiom(3).
Making the following paragraph false:
The first incompleteness theorem states that in any consistent formal
system F within which a certain amount of arithmetic can be carried
out, there are statements of the language of F which can neither be
proved nor disproved in F. (Raatikainen 2018)