This is my second in a series of posts reviving @PhilX's old posts on infinity in order to clarify some issues of philosophical interest and importance. The first thread in this series is
viewtopic.php?f=26&t=15446, and it wouldn't hurt to read that one first if you haven't already. And if you have, it wouldn't hurt to read it again. I have some references listed in that post that I won't necessarily repeat here.
Philosophy Explorer wrote:I already know that Aleph followed by a number characterizes the relative size of some infinite set. Let's start with Aleph 0.
The Alephs are indexed by the ordinal numbers. Technically the Alephs are also defined as certain ordinals (specifically, the least ordinal of any class of cardinally-equivalent ordinals) so that the Alephs are well-ordered by construction.
Philosophy Explorer wrote:
Aleph 0 is characterized by the set of natural numbers.
Aleph-0 is the cardinality of the natural numbers, yes. I'm not sure what you mean by "characterized by," that's a little vague.
Philosophy Explorer wrote:Aleph 0 is also characterized by set of nontranscendental irrational numbers.
Yes, but your terminology is a little odd. The algebraic numbers have cardinality Aleph-0. The algebraic numbers are the real numbers that are the roots of polynomials having integer coefficients. It's true but confusing to talk about "nontranscendental irrationals," since the rationals are algebraic as well.
Philosophy Explorer wrote:Why? Because the set of nontranscendental numbers may be placed in one-to-one correspondence with the set of natural numbers so these sets are the same size.
Yes but why? The proof is that there are only countably many roots of polynomials of degree 1; only countably many of degree 2; dot dot dot; and the union of a countable collection of countable sets is countable. So there are only countably many algebraic numbers.
Philosophy Explorer wrote:
Next we have Aleph 1 which may be characterized by the set of transcendental numbers (you know, those numbers that can't be the roots of any algebraic equation such as π and e).
Your terminology is funny again. (Funny odd, not funny haha). You are thinking of the real numbers, which include the transcendentals and the algebraic numbers.
The claim that the real numbers have cardinality Aleph-1 is the Continuum Hypothesis (CH), which you consistently mis-state in your posts. For all we know (and many set theorists believe), the cardinality of the real numbers is very large, far larger than Aleph-1. CH is independent of ZFC, so the question of whether there is a "true" answer is a matter of philosophy. Nevertheless, CH and related questions have been the object of intense study by set theorists since the time of Cantor and continuing to the present day.
But (this bears repeating, since you consistently misunderstand it) CH says that the cardinality of the reals is Aleph-1. But for all we know, it's Aleph-47. Or bigger. Nobody knows. It's a question of philosophy as to whether the question's even meaningful.
Philosophy Explorer wrote:
Now I have seen proofs showing the set of Aleph 1 numbers can't be placed into one-to-one correspondence with the set of Aleph 0 numbers. What I haven't seen is a proof showing the set of Aleph 1 is greater than the set of Aleph 0 (ironically I know that the set of Aleph 1 numbers are harder to find along the real number line than the set of Aleph 0 numbers, just like dark matter).
Aleph-0 is strictly less than Aleph-1 for the reason that both are defined as particular ordinals, and ordinals are well-ordered. Aleph-0 is the least member of the class of all countable ordinals. Aleph-1 is the least member of the class of all uncountable ordinals. See the Wiki references in my earlier infinity post to learn about well-orders and ordinal numbers.
Philosophy Explorer wrote:
Then we have Aleph 2 numbers which is characterized by all the curves (including, I presume, straight lines).
No, that's not true. I'll say why in a moment.
Philosophy Explorer wrote:
Why is this set characterized this way I don't know.
Why you make this claim, I don't know. I believe Cantor might have thought this was the case, but it turns out to be false, as we'll see in a moment.
Philosophy Explorer wrote:
Why is this set greater than Aleph 1 I don't know either.
Aleph-2 is strictly greater than Aleph-1 by the construction of the Alephs. They're particular ordinals. They line up like soldiers, one after the other: Aleph-0, Aleph-1, Aleph-2, etc. If any two of them were bijectively equivalent, they'd be the same Aleph by definition.
Philosophy Explorer wrote:
If somebody can shed light on this I'd appreciate it along with any commentary on higher sets than Aleph 2.
I take you at your word that you appreciate my attempt to help you sort out these ideas.
If you want to visualize the Alephs, that's easily done. 0, 1, 2, ... are the finite ordinals. Aleph-0 is the cardinality of the set of finite ordinals. Likewise, Aleph-1 is the cardinality of the set of ordinals of cardinality Aleph-0. Aleph-2 is the cardinality of the set of ordinals of cardinality Aleph-1, and so forth. Each Aleph is the cardinality of the set of ordinals having cardinality strictly less than that Aleph. In this way one can actually visualize each of the Alephs.
Philosophy Explorer wrote:
Edit: I gave Aleph 2 some more thought and here is my reasoning. The Aleph 1 level can be the entire real number line which can be composed of the transcendental numbers, the nontranscendental numbers and the set of natural numbers plus those negative counterpart numbers plus the fractions plus zero to round it out.
Again, your terminology is correct but very confusing. 0 is already algebraic, as are all the integers (positve and negative) and all the rationals (positive and negative). You can simply say that the reals consist of the transcendentals and the algebraics.
As to whether the reals have cardinality Aleph-1, again that is the content of CH. The reals may have cardinality Aleph-1, or they may have cardinalty Aleph-47. Or some other cardinality. The reals may have a cardinality of pretty much any Aleph at all, subject to some technical restrictions.
Philosophy Explorer wrote:
Okay then it would seem that the number of curves would be the next logical step up.
No, the set of curves has the same cardinality as the set of real numbers, as I'll show in a moment.
Philosophy Explorer wrote:
Now here's the thing. How would one number the curves for comparison purposes? For example, what number would be assigned to a parabolic curve as opposed to a hyperbolic curve? And then how would one go from there to proving that Aleph 2 is greater than Aleph 1? That's the extent of my knowledge.
This is how we calculate the number of curves.
First, what is a curve in the plane? It's a continuous curly line, intuitively speaking. How shall we formalize this? A curve in the plane is a
continuous function from the unit interval [0,1] to the plane R^2. If you think about it, that makes perfect sense. In includes all the straight line segments, the curvy lines, the closed curves, the curves that loop around and intersect themselves, and so forth.
Now a continuous function whose domain is some interval of real numbers is entirely characterized by its value on the rational numbers in that interval. That's because continuous functions preserve limits of sequences, and every real number is the limit of a sequence of rationals.
In other words in calculus class they tell you that if (x_n) is a sequence converging to x, and f is a continuous function, then the sequence (f(x_n)) converges to f(x). Every real number is the limit of the sequence of rationals formed by truncating its decimal expression. For example pi is the limit of the sequence of rationals 3, 3.1, 3.14, 3.141, ... Therefore if we know the value of a continuous function on the rational numbers, we automatically know its value on the real numbers. Continuity is a powerful condition that greatly restricts how wild a function can be.
Using cardinal arithmetic, the number of such continuous functions is therefore ((Aleph-0)^2) ^ (Aleph-0) = 2^(Aleph-0), which is the cardinality of the reals (ask me for that proof if you're interested).
https://en.wikipedia.org/wiki/Cardinal_ ... arithmetic
See this thread for the same answer but with better formatting. Why is there no LaTeX on this forum?
http://math.stackexchange.com/questions ... -2-aleph-0