Re: Resolution of the question as to whether math is discovered or invented
Posted: Tue Jun 10, 2025 11:36 am
For the discussion of all things philosophical.
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In first-order logic, ZFC shows more than PA. Then, you have the somewhat crippled maps, such as Robinson, Presburger, or Skolem, that show a lot less.
DeepSeek
Robinson Arithmetic (Q) extended with the axiom ∃c (Sc = c).
Incompatible with PA because PA proves that no number is equal to its own successor.
This theory demonstrates that a consistent numerical system can exist that contradicts PA, leveraging the absence of the full induction schema in Q to allow non-standard elements like the fixed-point number c.
Your head's up in the sky again. Or rather - right up your ass.godelian wrote: ↑Tue Jun 10, 2025 12:15 pmIn first-order logic, ZFC shows more than PA. Then, you have the somewhat crippled maps, such as Robinson, Presburger, or Skolem, that show a lot less.
In fact, I don't know of maps that support a concept of numbers, are incompatible with PA, but are still consistent. It's certainly not excluded that they exist. It seems to be easier to discover alternative geometries than alternative arithmetics.
DeepSeek came up with one but it is not particularly impressive. It looks more like a contorted corner case:
DeepSeek
Robinson Arithmetic (Q) extended with the axiom ∃c (Sc = c).
Incompatible with PA because PA proves that no number is equal to its own successor.
This theory demonstrates that a consistent numerical system can exist that contradicts PA, leveraging the absence of the full induction schema in Q to allow non-standard elements like the fixed-point number c.
Look at how addition and multiplication are defined in PA:
How 0 functions in any given theory is neither here nor there.godelian wrote: ↑Tue Jun 10, 2025 3:25 pm Look at how addition and multiplication are defined in PA:
Addition:
base: a+0=a
recurse: a+S(b)=S(a+b)
Multiplication:
base: a*0=0
recurse: a*S(b)=a+(a*b)
Without a definition for 0, you have to scrap the definition for the base case for the addition. The recursion wouldn't terminate anymore. So, you won't be able to define the addition, which is in turn necessary for the recurse case in the multiplication. So, you won't be able to define the multiplication either.
Consequently, addition and multiplication are no longer defined. Therefore, it is no longer an arithmetic.
Maybe there are workarounds and alternative solutions possible by judiciously hacking PA, but simply removing the definition for zero won't work.
That remark is a bit facile. You originally asked about PA with or without zero. The answer is that PA without zero is no longer an arithmetic theory, because the definitions of addition and multiplications would blow up. It is not possible to arbitrarily remove something or change the definition of PA, because it all hangs together. Your question amounts to asking if you can just remove an arbitrary line here or there from an existing program. Chances are that you can't.
I didn't invent anything there, that's just what was taught as most essential preliminaries at my university in the most basic philosophy class there was ("Philosophische Propädeutik").Skepdick wrote: ↑Fri Jun 06, 2025 11:16 amSo you've invented a new ontological category of "neither physical nor mental abstract objects" to account for pre-existing classes.luberti wrote: ↑Fri Jun 06, 2025 8:29 am Under common ontological notions, you obviously cannot describe a class that doesn't already exist, since they all exist as abstract objects as soon as they are classes. Also a class didn't come into existence. It exists independently of time since it is neither a physical nor a mental object.
You're full of shit, or that's a straw man (idk what you mean by "ontological" or why you believe it would even matter). You cannot talk about something when it is not a thing. Ontology is about categorizing _all_ things. Anyway, I'm not gonna argue definitions. When you refuse to use certain definitions, you simply cannot talk about certain things. Not my problem.
That's bullshit. Grammar is syntactical, i.e. concerns form, whereas meaning is semantical, i.e. concerns models.Skepdick wrote: ↑Fri Jun 06, 2025 11:16 am
Solved? You didn't even define/specify what the question was. What is this abstract "problem" you are solving? Where can I discover it?
No, this is not "just basic semantics".
It's just basic grammar.
What do you mean by "exists" (a verb - and therefore a temporal notion)... "independently of time".
This is grammatically incoherent.
Your basic use of language is broken
Until Peano and Dedekind finally managed to discover one in the late 19th century, there was no axiomatic theory for arithmetic, to the extent that a century earlier Kant had even claimed in his Critique of Pure Reason that there simply wasn't one:
If axiomatic theories are mere inventions, then why didn't some inventor just liberally invent an axiomatic theory for arithmetic? That should have been easy, no? If it is just an invention?Arithmetic has no axioms. ... Its propositions are all synthetic, without being derived from general concepts alone, but through the construction of magnitudes in time.
Critique of Pure Reason, A164/B205
OK, so somebody else invented it. You discovered, or more precisely - you were indoctrinated with the invention.
I mean the same thing everyone means when they use the word. I also mean NON-epistemic.
Aaaah, you see! There lies your confusion. Ontology is about what exists. Categorizing existence (synthesizing taxonomies) is epistemic.
We aren't arguing definitions. We are arguing fundamental categories. And more importantly - we are arguing about how ontology relates to epistemology and vice versa.
I guess we'll have to agree to disagree. I use language to invent definitions - I don't presuppose them.
I know that. Which is why I was explaining your grammatical/syntax error.
You appear to have misunderstood the assigned. You failed to define the question.
You get 100000000000000000 points for irony.
I didn't. Why are you lying?
Who cares? I am not interested in a theory of arithmetic. I am interested in true statements about the Platonic realm.godelian wrote: ↑Tue Jun 10, 2025 4:38 pm The answer is that PA without zero is no longer an arithmetic theory , because the definitions of addition and multiplications would blow up. It is not possible to arbitrarily remove something or change the definition of PA, because it all hangs together. Your question amounts to asking if you can just remove an arbitrary line here or there from an existing program. Chances are that you can't.
There is nothing to say about "any theory". Context-free does not exist in mathematics. There is always a context. Otherwise, it is not mathematics.
Yes, but there was nothing provable about arithmetic without theory. Same for geometry. You don't need a theory for geometry, but you won't prove anything about it, if you go ahead without a theory.
Aboriginal mathematics is fine. It's what most people still use today in daily life.https://en.wikipedia.org/wiki/Informal_mathematics
Informal mathematics, also called naïve mathematics, has historically been the predominant form of mathematics at most times and in most cultures, and is the subject of modern ethno-cultural studies of mathematics.
Informal mathematics means any informal mathematical practices, as used in everyday life, or by aboriginal or ancient peoples, without historical or geographical limitation. Modern mathematics, exceptionally from that point of view, emphasizes formal and strict proofs of all statements from given axioms. This can usefully be called therefore formal mathematics. Informal practices are usually understood intuitively and justified with examples—there are no axioms.
OK. Lets work with that.
You have to say what A and B are. Otherwise, there is nothing to say about A or B.Skepdick wrote: ↑Wed Jun 11, 2025 9:43 amOK. Lets work with that.
In context of the Platonic ream which class of theories is true?
A or B?
I am not going to entertain the rest of the evasion.