Distinctions as Self-Contained Self-Contrast; Meta-Formalism

What is the basis for reason? And mathematics?

Moderators: AMod, iMod

Post Reply
Eodnhoj7
Posts: 10755
Joined: Mon Mar 13, 2017 3:18 am

Distinctions as Self-Contained Self-Contrast; Meta-Formalism

Post by Eodnhoj7 »

----++++****Updated

Distinctions as Self-Contained Self-Contrast; Meta-Formalism

"A" identity, distinction
"=" is or equals
"( )" context, container, set
"○" Scale invariant self referencing context
"<->" biconditional
"-" absence, negation
"+" presence, emergence

1. A

2. A=A

3. ((A=A) <-> (-A=-A)) <->
((A=/=-A) <-> (A = - -A))

4. (A <-> -A) <-> ((A=A) <-> (-A=-A))

5. (A <-> -A) = B

6. B = B

7. (B = B) <-> (-B=-B) <->
((B =/= -B) <-> (B = - -B))

8. (B <-> -B) <-> ((B=B) <-> (-B=-B))

9. (B <-> -B) = C

10. ....D....

11. (A <-> A) = (B <-> -B) = (C <-> -C) =...

12. ● <-> - ●

13 (● <-> - ●) <-> ((● =/= - ●)
<-> (● = - -●))

14. ● = (+,-)

15. (+, -)

16. ( )

17. ( ) = ( )

18. (( ) <-> -( )) <->
((( ) =/=( )) <-> (( )=--( )))

19. (( ) <-> -( )) <-> (( ))

20. (( )) = (( ))

21. ...(..(( ))..)...

22. ○

23. A = ( )
A = ○
● = ( )
● = ○
( ) = ○

24. (A <-> ● <-> ( ) <-> ○) = X
X1 = A
X2 = ●
X3 = ( )
X4 = ○

25. (X = (X1, X2, X3, X4)) <->
(((X = X1) <-> Y1),
((X = X2) <-> Y2),
((X = X3) <-> Y3),
((X = X4) <-> Y4))
Y(1,2,3,4) = ( )

****

26. X <-> Y

27. (A) <-> (●) <-> (( )) <-> (○)

28. ...(..(( ))..)...

29. (( )<->( )) = ((( )=( )),(-( )=-( )))

30. (<->)=(+=+, -=-) <-> (( )<->( ))

31. ((+=+) <-> (-=-)) = ((--=--)<->(++=++))

32. ((=) <-> (=)) = ((=) <-> (=))

33. (<->,=)

34. (<->)<->(<->),
(=)<->(=)
(<->)=(<->)
(=)=(=)

35. ( )=( ), ( )<->( )

36. ( )

37. ( )( ) = (+1,A)

38. ( )( )( ) = (+1,+2,-1, +A,+B,-A)

39. ( )( )( )( ) =
(1,2,3,-1,-2,+A,+B,+C,-A,-B)

40. ( )( ) ( )( )( ) = (3,-1, +C, -A)

41. ( )( ) ( )( )( )( ) = (×4, -2, +D, -B)

42. ( )( ) ( )( )( )( )( ) =
(+5, -3, +E, -C)


43. (( )( )) = (+1,+A)

44. ((( )( ))) = (+2, +1/2, +B, +A/B)

45. (((( )( )))) = (+3, +1/3, +C, +A/C)

46. ( )....( ) = (+n, -n+1, +N, -N+A)

47. (..(..( )..)..) = (+n, +A/n, +N, +A/N)

48. (..( )..)(..( )..) = (1 inf., A continuum)

49. (..( )..)(..( )..)(..( )..) = 2 inf., -1 inf., B cont., -A cont.)

50. ......

51. (..( )..)(..( )..) (..( )..)(..( )..)(..( )..) =
(+3inf, -1inf, +C[continuum], -A[Cont.]

52. (..( )..)(..( )..) (..( )..)(..( )..)(..( )..)(..( )..) = (+4inf. , -2inf., +D cont., -B cont.)

53. ((..( )..)(..( )..)) = (+1 inf., +A cont.)

54. (((..( )..)(..( )..))) = (+2 inf., +1/2 inf., +B cont., +A/B cont.)

55. (..( )..)...(..( )..) = (+n inf. -n inf.+1 inf., +N cont., -N cont.+A cont.)

56. (..(..( )..)..)inf. = (+n inf., +A/n inf., +N cont, +A/N cont.)

57. (..(..( )..)..) <-> (..(..( )..)..)inf.
Post Reply